Join Date: Mar 2012
Location: Outer Banks, NC
Breeding for appearance questions
This is sort of a spin off from my recent thread "what kind of dog is that?". I've had a few conversations about how you can have a purebred GSD with long hair and a sable coat. This generally comes from those people who swear Kaiser is mixed with "something".
For starters, I know the sable gene is dominant but I'm not sure about coat length. In Kaiser's case, I think he has a medium length stock coat (he still has an undercoat, although his fur is much less coarse than the "standard" calls for). I admit, until I saw Falon's Kastle, I had never seen another longer haired sable in the US. So for my personal knowledge, how does this work?
For example, if Kaiser was to be bred to a very dark stock coat sable, how would the puppies (theoretically) look? What if the female was a longer coat?
What would the puppies look like if Kaiser was bred to a standard b&t or r&b?
And what about a pure black or pure white?
Obviously none of these breedings will ever occur as I have absolutely no plans on breeding Kaiser and NOBODY should EVER breed for just appearance. I'm just trying to understand the genetics of it, as best I can. I know the basics of genetics in that both parents have to have the recessive gene in order to produce puppies with that recessive trait...and I know that a dominant gene will trump a recessive gene. But beyond that...
And as an aside, I'm having trouble finding dogs with Belgium roots online. Does anyone have any examples you could show me of both short and longer coated belgian lines?
Kaiser ~ Jan 25, 2012 (GSD)
Dakota ~ Oct 2005 (GSD/Collie)
Kya ~ (Cat)
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